BLAM

2009-12-27 22:04:54 by x55673x

(%u25CF%u032A%u2022)=%u03B5/%u0335%u03 47%u033F%u033F/'%u033F'%u033F%u033F%u0 33F %u033F %u033F%u033F %u033F %u033F %u0669%u0E4F%u032F%u0361%u0E4F%u06F6 %u033F %u033F %u033F %u033F %u033F%u033F'\%u0335%u0347%u033F%u033F \=(%u2022%u032A%u25CF) blahh blahhh


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